Is there a solution to $x^2+y^2=1992$ for positive integers $x$ and $y$?

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$x^2+y^2=1992---(A)$
pove $(A)$ has no positive integer solution
 
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Albert said:
$x^2+y^2=1992---(A)$
pove $(A)$ has no positive integer solution

repeat question http://mathhelpboards.com/challenge-questions-puzzles-28/prove-x-y-1992-no-solution-13109.html?highlight=1992
 

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