- #1

lark

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So would differentiable functions from Qp

*-> Qp*

*satisfy the*

Cauchy-Riemann equations? I don't know why not.

To what extent would analysis in QpCauchy-Riemann equations? I don't know why not.

To what extent would analysis in Qp

*have the familiar complex analysis*

theorems? You couldn't prove that Qptheorems? You couldn't prove that Qp

*is algebraically complete, I*

wonder what would block the complex analysis proof of that, that 1/p(x)

would be a bounded entire function if it had no roots.

Laurawonder what would block the complex analysis proof of that, that 1/p(x)

would be a bounded entire function if it had no roots.

Laura