- #1
AxiomOfChoice
- 533
- 1
If we're attempting to solve
[tex]
H\psi = E\psi
[/tex]
where [itex]H[/itex] is real and Hermitian, are we allowed to assume [itex]\psi[/itex] is real? Why or why not? My gut tells me the answer is "yes," since we know [itex]E[/itex] is real, but I can't make my idea rigorous.
[tex]
H\psi = E\psi
[/tex]
where [itex]H[/itex] is real and Hermitian, are we allowed to assume [itex]\psi[/itex] is real? Why or why not? My gut tells me the answer is "yes," since we know [itex]E[/itex] is real, but I can't make my idea rigorous.