Is There an Android App for Bingo Statistics?

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An individual is seeking an Android app to track bingo statistics for a TV game where players choose 20 numbers from 75. The goal is to analyze which numbers are drawn less frequently and which are perceived as "luckier." There is skepticism about the randomness of the game, with suggestions that patterns may exist in the balls used. Concerns are raised regarding the costs associated with playing and the potential for the games to be more about generating revenue than fair play. The discussion highlights the need for tools to analyze game statistics while questioning the integrity of the game itself.
bucek
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hi.

please help. `im searching for an android app for bingo statistics.

there is a tv game for bingo. each week there is a game you choose 20 numbers (4 numbers in each row) from 75.

if someone using one, would be thankfull to hear from you.

thanks in advance
 

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Isn't it random, like lotteries?
 
Hi, ser.

My point is to record numbers and watch statisticly, which numbers in % choose less and which nunbers is more lucky.

I heard that you need to play always with one combination and one day you will win. :)
 
Well, it's not the numbers that are lucky. If there is any pattern, it will be in the balls themselves. And I imagine they change those regularly.

How much do you pay for a shot at these games? Is it 50c per call? How much do you win? How long do you have to play to win?

Finally, you do realize that these games are stacked? It is not a game; it is phone charge business. They make money when you call. There is no reason why they would have to pay out.
 
The standard _A " operator" maps a Null Hypothesis Ho into a decision set { Do not reject:=1 and reject :=0}. In this sense ( HA)_A , makes no sense. Since H0, HA aren't exhaustive, can we find an alternative operator, _A' , so that ( H_A)_A' makes sense? Isn't Pearson Neyman related to this? Hope I'm making sense. Edit: I was motivated by a superficial similarity of the idea with double transposition of matrices M, with ## (M^{T})^{T}=M##, and just wanted to see if it made sense to talk...

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