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Is there any equivalent for Ln(1+ax)?

  1. Jan 28, 2013 #1
    Hello friends,
    I would like to know the equivalent expression/function for Ln(1+ax), where 'a' is constant. I am not interested in series expansion, I would like to know whether it can be written in terms of sum of other simple terms/functions ( It can be trigonometric, hyperbolic, etc.,)

    Thank you
  2. jcsd
  3. Jan 28, 2013 #2


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    Staff: Mentor

    There are different ways to write ln(1+ax), but they are all more complicated.
  4. Jan 28, 2013 #3
    This is a pretty ambiguous question. There are many ways to write an equivalency. Without knowing more specifically what you are trying to do, it would be hard to give you an answer that would work for you.

    alternatively, you can explore wolfram and see where that takes you I suppose.
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