Is there enough torque in the motor for the system?

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SUMMARY

The discussion centers on evaluating the torque capacity of the Ampflow A28-400 motor for a rotary to linear pressure cycling system. The motor provides 177.01 in*lb of torque at 1100 RPM, while the air cylinder generates a force of 1227 lbs at 250 psi. Calculations indicate that the torque required to cycle the system exceeds the motor's output, suggesting that the current motor is insufficient for the task. Participants emphasize the need for a comprehensive kinematic and dynamic analysis, including the creation of a P-V diagram to accurately assess the system's performance.

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  • Understanding of torque calculations in mechanical systems
  • Familiarity with pneumatic systems and pressure dynamics
  • Knowledge of gear ratios and their impact on torque
  • Ability to perform kinematic and dynamic analysis
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  • Conduct a detailed kinematic analysis of the rotary to linear pressure cycling system
  • Learn how to create and interpret a P-V diagram for pneumatic systems
  • Research the effects of varying pressure on air cylinder performance
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Epiphany Man
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Good morning,

I have little problem here and I've come here with hopes of a solution!
I'm currently messing with a rotary to linear pressure cycling system. The size of the air cylinder has already been decided and I'm simply trying to design around it.

Here are the specifics! I've added a picture of the rough model.

http://imgur.com/1co9b7u
http://imgur.com/1co9b7u

Starting from left to right...

The motor I'm thinking of is the...

Ampflow A28-400

Torque @ 1100 RPM = 177.01 in*lb.

1st Spur Gear (Pinion)

Radius : .3 in
17 teeth

2nd Spur

Radius: 3.5 in
120 teeth


Rectangle bar attached to the spur gear and rod clevis(w/ pin)

Length : 5 in

Air cylinder

Produces a force of 459 lbs @ 100 psi
Stroke 6"
Diameter 2.5"

------------------------------------------------------------------------------------------------------------------------------------------------
Attempted
Calculations

Torque from Air Cylinder ONLY.

I want to see if the torque supplied by the current motor is enough if I wanted to cycle 250 psi.

Force(Air cylinder @ 250 psi)

[F = P*pi*(d^2/4)]

F = (250 lb/in^2)(3.14)(2.5^2/4) = 1227 lbs (Needed to move)

Torque needed @ 250 psi (w/ rectangle bar)

[T = F * d]

T = (1227 lb)(5 in) = 6135 lbs ( This is where I believe I'm totally off.)-----------------------------------------

Torque from MOTOR w/ GEARs

Find the force from motor to spur 1

[F1 = T1/r1]

F = 177.01 in*lb/.3 in = 590.03 lbs

Find torque in spur 2

[T2 = F1 * r2]

T2 = (590.03 lbs)(3.5 in) = 2065.00 lbs
From my calculations, there is no way this motor can do its job but the numbers seem crazy high to me. Am I performing these calculations correctly? If so, would there be anything you guys can suggest?Thank you for your future assistance!
 
Last edited:
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Your equation T = F*d is wrong. Torque is force times radius, but that is only the beginning of your difficulties.

You need to make a proper kinematic and dynamic analysis of this device, remembering that the cylinder pressure is not 250 psi all the time at all. You need to put together a P-V diagram for your cycle, all for energy storage in the moving parts, and write the complete system equation of motion. Only then will you be anywhere close to evaluating the suitability of the motor.
 

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