- #1
Epiphany Man
- 1
- 0
Good morning,
I have little problem here and I've come here with hopes of a solution!
I'm currently messing with a rotary to linear pressure cycling system. The size of the air cylinder has already been decided and I'm simply trying to design around it.
Here are the specifics! I've added a picture of the rough model.
http://imgur.com/1co9b7u
http://imgur.com/1co9b7u
Starting from left to right...
The motor I'm thinking of is the...
Ampflow A28-400
Torque @ 1100 RPM = 177.01 in*lb.
1st Spur Gear (Pinion)
Radius : .3 in
17 teeth
2nd Spur
Radius: 3.5 in
120 teeth
Rectangle bar attached to the spur gear and rod clevis(w/ pin)
Length : 5 in
Air cylinder
Produces a force of 459 lbs @ 100 psi
Stroke 6"
Diameter 2.5"
------------------------------------------------------------------------------------------------------------------------------------------------
Attempted Calculations
Torque from Air Cylinder ONLY.
I want to see if the torque supplied by the current motor is enough if I wanted to cycle 250 psi.
Force(Air cylinder @ 250 psi)
[F = P*pi*(d^2/4)]
F = (250 lb/in^2)(3.14)(2.5^2/4) = 1227 lbs (Needed to move)
Torque needed @ 250 psi (w/ rectangle bar)
[T = F * d]
T = (1227 lb)(5 in) = 6135 lbs ( This is where I believe I'm totally off.)-----------------------------------------
Torque from MOTOR w/ GEARs
Find the force from motor to spur 1
[F1 = T1/r1]
F = 177.01 in*lb/.3 in = 590.03 lbs
Find torque in spur 2
[T2 = F1 * r2]
T2 = (590.03 lbs)(3.5 in) = 2065.00 lbs
From my calculations, there is no way this motor can do its job but the numbers seem crazy high to me. Am I performing these calculations correctly? If so, would there be anything you guys can suggest?Thank you for your future assistance!
I have little problem here and I've come here with hopes of a solution!
I'm currently messing with a rotary to linear pressure cycling system. The size of the air cylinder has already been decided and I'm simply trying to design around it.
Here are the specifics! I've added a picture of the rough model.
http://imgur.com/1co9b7u
http://imgur.com/1co9b7u
Starting from left to right...
The motor I'm thinking of is the...
Ampflow A28-400
Torque @ 1100 RPM = 177.01 in*lb.
1st Spur Gear (Pinion)
Radius : .3 in
17 teeth
2nd Spur
Radius: 3.5 in
120 teeth
Rectangle bar attached to the spur gear and rod clevis(w/ pin)
Length : 5 in
Air cylinder
Produces a force of 459 lbs @ 100 psi
Stroke 6"
Diameter 2.5"
------------------------------------------------------------------------------------------------------------------------------------------------
Attempted Calculations
Torque from Air Cylinder ONLY.
I want to see if the torque supplied by the current motor is enough if I wanted to cycle 250 psi.
Force(Air cylinder @ 250 psi)
[F = P*pi*(d^2/4)]
F = (250 lb/in^2)(3.14)(2.5^2/4) = 1227 lbs (Needed to move)
Torque needed @ 250 psi (w/ rectangle bar)
[T = F * d]
T = (1227 lb)(5 in) = 6135 lbs ( This is where I believe I'm totally off.)-----------------------------------------
Torque from MOTOR w/ GEARs
Find the force from motor to spur 1
[F1 = T1/r1]
F = 177.01 in*lb/.3 in = 590.03 lbs
Find torque in spur 2
[T2 = F1 * r2]
T2 = (590.03 lbs)(3.5 in) = 2065.00 lbs
From my calculations, there is no way this motor can do its job but the numbers seem crazy high to me. Am I performing these calculations correctly? If so, would there be anything you guys can suggest?Thank you for your future assistance!
Last edited: