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I have little problem here and I've come here with hopes of a solution!

I'm currently messing with a rotary to linear pressure cycling system. The size of the air cylinder has already been decided and I'm simply trying to design around it.

Here are the specifics! I've added a picture of the rough model.

http://imgur.com/1co9b7u

http://imgur.com/1co9b7u

Starting from left to right...

The motor I'm thinking of is the....

Ampflow A28-400

Torque @ 1100 RPM = 177.01 in*lb.

1st Spur Gear (Pinion)

Radius : .3 in

17 teeth

2nd Spur

Radius: 3.5 in

120 teeth

Rectangle bar attached to the spur gear and rod clevis(w/ pin)

Length : 5 in

Air cylinder

Produces a force of 459 lbs @ 100 psi

Stroke 6"

Diameter 2.5"

------------------------------------------------------------------------------------------------------------------------------------------------

AttemptedCalculations

Torque from Air Cylinder ONLY.

I want to see if the torque supplied by the current motor is enough if I wanted to cycle 250 psi.

Force(Air cylinder @ 250 psi)

[F = P*pi*(d^2/4)]

F = (250 lb/in^2)(3.14)(2.5^2/4) =(Needed to move)1227 lbs

Torque needed @ 250 psi (w/ rectangle bar)

[T = F * d]

T = (1227 lb)(5 in) =6135 lbs(This is where I believe I'm totally off.)

-----------------------------------------

Torque from MOTOR w/ GEARs

Find the force from motor to spur 1

[F1 = T1/r1]

F = 177.01 in*lb/.3 in =590.03 lbs

Find torque in spur 2

[T2 = F1 * r2]

T2 = (590.03 lbs)(3.5 in) =2065.00 lbs

From my calculations, there is no way this motor can do its job but the numbers seem crazy high to me. Am I performing these calculations correctly? If so, would there be anything you guys can suggest?

Thank you for your future assistance!

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# Is there enough torque in the motor for the system?

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