- #1
Cypeq
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[itex]ax^{''} = 0[/itex]
characteristic eqation
[itex]ar^{2} = 0[/itex]
[itex]r_{1,2} = 0[/itex]
since we have double result
[itex]x(t) = c_{1}e^{0t} + c_{2}t e^{0t}[/itex]
so [tex] e^0 = 1 [/tex]
[tex]x(t) = c_{1} + c_{2}t[/tex]
is this a correct result :S ? I'm learning integration by myself and I'm not shure about this case it's not cover in my book if results can be zero or it doesn't matter :S ?
characteristic eqation
[itex]ar^{2} = 0[/itex]
[itex]r_{1,2} = 0[/itex]
since we have double result
[itex]x(t) = c_{1}e^{0t} + c_{2}t e^{0t}[/itex]
so [tex] e^0 = 1 [/tex]
[tex]x(t) = c_{1} + c_{2}t[/tex]
is this a correct result :S ? I'm learning integration by myself and I'm not shure about this case it's not cover in my book if results can be zero or it doesn't matter :S ?
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