[itex]ax^{''} = 0[/itex](adsbygoogle = window.adsbygoogle || []).push({});

characteristic eqation

[itex]ar^{2} = 0[/itex]

[itex]r_{1,2} = 0[/itex]

since we have double result

[itex]x(t) = c_{1}e^{0t} + c_{2}t e^{0t}[/itex]

so [tex] e^0 = 1 [/tex]

[tex]x(t) = c_{1} + c_{2}t[/tex]

is this a correct result :S ? i'm learning integration by myself and i'm not shure about this case it's not cover in my book if results can be zero or it doesn't matter :S ?

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# Is this a correct solution ? to ax'' = 0

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