- #1

ineedhelpnow

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$y''+3y'+2y=2x^{2}+4x+5$$r^{2}+3r+2=0$

$r=-2$ and $r=-1$

$y_{h}=c_{1}e^{-2x}+c_{2}e^{-x}$

I'm not sure how to get $y_{p}$ here

So here's what I've done so far. I have my final exam tomorrow and I have a few questions to go over as a review. I need help with the rest of this!

Here's another one:

$y''+3y''+3y'+y=e^{x}-x-1$

$r^{3}+3r^{2}+3r+1=0$

$r_{1,2,3}=-1$

$y_{h}=c_{1}e^{-x}+xe^{-x}(c_{2}+c_{3})$

Not really sure how to get $y_{p}$ here either