MHB Is This an Example of Absolute Value Inequalities?

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The discussion centers on solving the absolute value inequality |(4 - 5x)/2| > 1. Participants confirm that the theorem stating |u| > a implies u < -a or u > a can be applied. The inequality can be rewritten and simplified by multiplying through by 2, leading to |x - 4/5| > 2/5. The solution is straightforward once the absolute value is isolated. This confirms that the original problem is indeed an example of absolute value inequalities.
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Solve the inequality.

| (4 - 5x)/2 | > 1

Can I use the following theorem?

If a > 0, then | u | > a if and only if u < -a or u > a
 
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Yes, you can: either $$\frac{4- 5x}{2}> 1$$ or [math]\frac{4- 5x}{2}< -1[/math]. Continue, with either equation, by multiplying both sides by the positive number, 2.
 
I can take it from here.
 
RTCNTC said:
Solve the inequality.

| (4 - 5x)/2 | > 1

Can I use the following theorem?

If a > 0, then | u | > a if and only if u < -a or u > a

We are given:

$$\left|\frac{4-5x}{2}\right|>1$$

Multiply through by 2/5:

$$\left|x-\frac{4}{5}\right|>\frac{2}{5}$$

Now the solution is easy to read off...:D
 
Is the question what is known as absolute value inequalities?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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