Is this Cylinder Strong Enough to Open This Door?

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The discussion centers on the feasibility of using a Pneumatic Plunger to open a heavy door weighing 136 pounds, with dimensions of 40 inches in width and 80 inches in height, within one second. The plunger operates at a working pressure of 80 psi and has a maximum speed of 6.4 inches per second, which is insufficient for the required velocity of 125 inches per second to achieve a 180-degree rotation. To successfully operate the door, the plunger must be repositioned closer to the hinge line to reduce the radius, allowing for the necessary acceleration and energy transfer to prevent dangerous outcomes.

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I have this door that was designed to supposedly open for 180 degrees in 1 second. A Pneumatic Plunger was used to push the door. However I'm not sure if this was strong enough to open the door. Can this be counted as Partially Inelastic Collision?

DOOR:
m = 136pound
width = 40 inch
height = 80in

PLUNGER:
Working Pressure = 80psi
Bore Size = 1.5 inch
Stroke Size = 2 inch
Max speed = 6.4in/s
m = 1 lb

upload_2018-4-30_23-40-55.png
 

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Probably not.
The outer edge of the door where the cylinder plunger strikes is 40” from the hinge axis.
For a 180° rotation in one second, the minimum plunger velocity will need to be Pi * R = 125 inch/second.
Yet your plunger is rated at only 6.5 inch/sec.

You must reduce the radius by moving the plunger closer to the hinge line.
The door must accelerate to over 125 inch/sec during the very short travel of the plunger.
The energy in the compressed air must be sufficient to accelerate the door to high angular velocity.
A door like that is capable of killing people. You are designing a man trap.
 
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