MHB Is this equation true for positive values of x and y?

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The equation $y^2+x*\sqrt{4x^2+y^2}=y^2+\frac{x}{y}*\sqrt{4(\frac{x}{y})^2+1}$ is not true for positive values of x and y. The left side simplifies to $y^2+x \cdot |y| \cdot \sqrt{ \frac{4x^2}{y^2}+1}$, which, under the condition that y is positive, becomes $y^2+x \cdot y \cdot \sqrt{ \frac{4x^2}{y^2}+1}$. This indicates that the two sides of the equation do not equate as initially proposed. The discussion confirms the need for careful evaluation of mathematical expressions involving square roots and ratios. The conclusion is that the equation does not hold true for the specified conditions.
cbarker1
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Hello,

I need some aid to see if this true:

$y^2+x*\sqrt{4x^2+y^2}=y^2+\frac{x}{y}*\sqrt{4(\frac{x}{y})^2+1}$ provide that y>0 and x>0.Thank you,

Cbarker1
 
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Cbarker1 said:
Hello,

I need some aid to see if this true:

$y^2+x*\sqrt{4x^2+y^2}=y^2+\frac{x}{y}*\sqrt{4(\frac{x}{y})^2+1}$ provide that y>0 and x>0.Thank you,

Cbarker1

(Wave)

No. It holds that $y^2+x \cdot \sqrt{4x^2+y^2}=y^2+ x \cdot \sqrt{y^2 \left( \frac{4x^2}{y^2}+1\right)}=y^2+x \cdot |y| \cdot \sqrt{ \frac{4x^2}{y^2}+1}$.And provided that $y>0$, $y^2+x \cdot |y| \cdot \sqrt{ \frac{4x^2}{y^2}+1}=y^2+x \cdot y \cdot \sqrt{ \frac{4x^2}{y^2}+1}$
 
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