Is This Integration of e^-x / (1-e^-1) Correct?

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SUMMARY

The integration of the function e^-x / (1-e^-1) has been correctly simplified. The constant 1 / (1-e^-1) is factored out, leading to the integral of e^-x, which results in -e^-x. Thus, the final expression for the integral is -e^-x / (1-e^-1). This conclusion can be verified by differentiating the antiderivative to confirm its accuracy.

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willoconley
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It's been awhile since I've used integration, I guess I am a bit rusty with the calculus. I need to integrate:

e^-x / 1-e^-1 dx

1 / 1-e^-1 is pulled out of the integral and the integral of e^-x = -e^-x. So:

e^-x / 1-e^-1 dx = -e^-x / 1-e^-1

Could someone tell me if that is correct?
 
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Looks good to me. Remember, you could always check your answer by taking the derivative of the antiderivative. :wink:
 

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