Is this pre algebra problem correctly solved?

[eeeeee]

could some one help me fine the products with these problems.


-3x3(2x3 +3x-4)

 

[eeeeee]

the little 3s mean to the third power

 

[pendulum]

x1=x2=x3=0
x4=0.879615
x5= -0.439807 + i 1.44232
x6= -0.439807 - i 1.44232

I found arithmetically. I hope I'm right

 

[eeeeee]

I am pretty sure that is not the right answer

 

[eeeeee]

here are 2 others
1. (x+1)(x-2)2.(4x-2)(-x+3)

 

[pendulum]

I've just checked my answers and they are absolutely right.
Unless you are not asking for the solution of the
-3(x^3) ( 2(x^3) + 3x - 4) = 0
What you've written (about the 2 others) has nothing to do.

 

[eeeeee]

i need to find the product of

1. (x+1)(x-2)2.(4x-2)(-x+3)

 

[eeeeee]

nvm i figured it out

 

[pendulum]

(x+1)(x-2) = (x^2) -x -2 = 0 -> x1= 2
and x2= -1

(4x-2)(-x+3) = -4(x^2) +14x -6 =0 -> x1 = 3
and x2 = 0.5

But again, it has nothing to do with the first one.

 

[d_leet]

(x+1)(x-2) = (x^2) -x -2 = 0 -> x1= 2
and x2= -1

(4x-2)(-x+3) = -4(x^2) +14x -6 =0 -> x1 = 3
and x2 = 0.5

But again, it has nothing to do with the first one.

Stop assuming what is being posted are equations because they are not. Do you see an equal sign in any of the above posts exclusing your own? The OP has posted expressions asking for help in expanding them, there is nothing to solve for since there is no equation at all.

 

[vsage]

(Homework help should be posted in the homework help forums)

 

[pendulum]

Ok I'm sorry. Stop shooting! The problem is with my english.

 

[HallsofIvy]

"=" has nothing to do with "English"!

 

[pendulum]

I thought products meant roots.

 

[pendulum]

Again, you're right. I 'm sorry.

 

[Crusty]

^ means to the power of.
Is this right?

-3x^3(2x^3 +3x-4) = -6x^6 - 9x^4 + 12x^3

(x+1)(x-2) = x^2 + x - 2x -2 = x^2 - x - 2

(4x-2)(-x+3) = -4x^2 + 2x + 12x - 6 = -4x^2 + 14x - 6