Is this proof for a linear differential eq correct purely mathematically

Click For Summary
SUMMARY

The discussion centers on the mathematical validity of a proof related to linear differential equations, specifically addressing the treatment of the constant of integration. The participants confirm that expressing the constant of integration before performing the integral is acceptable, as constants can be combined. The emphasis is on understanding that the constant must be determined based on initial conditions, which simplifies the integration process. The conversation highlights the importance of clarity in mathematical proofs and the implications of constants in differential equations.

PREREQUISITES
  • Understanding of linear differential equations
  • Familiarity with integration techniques
  • Knowledge of constants of integration
  • Basic principles of mathematical proofs
NEXT STEPS
  • Study the properties of constants in integration
  • Explore the role of initial conditions in solving differential equations
  • Learn about the implications of combining constants in mathematical proofs
  • Review advanced techniques in solving linear differential equations
USEFUL FOR

Mathematicians, students studying differential equations, educators teaching calculus, and anyone interested in the rigor of mathematical proofs.

Pellefant
Messages
36
Reaction score
0
Is this proof for a "linear differential eq" correct purely mathematically

I wonder if this proof is correct purely mathematically
look at (3) in the link, and you will se that they have done the following ...

[tex]\int p(x)dx = \int p(x)dx +c[/tex]

So they have put out the constant of integration before they have done the integration, can they really do that?

http://www.bio.brandeis.edu/classes/biochem102/hndDiffEq.pdf
 
Last edited by a moderator:
Physics news on Phys.org
Yes, since constant + constant = constant. They probably did that to emphasize that a constant will have to be worked out to fit some initial conditions.
 
Yea it makes it much easier because then you don't need to think about constant of integration ... In my brain i can see that as mathematically correct if c=0 because e^0=1 ...

I am fairly sure that you can't say c1+c=c2, for a value where c isn't cero, because the value from the integration (which gives c1) can just be the exactly correct value form that integration ...

Sorry if i am concerned about stuff that don't matter, but for me it is important for my understanding ...

Kindly Pellefant ...
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
0
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 21 ·
Replies
21
Views
2K
Replies
2
Views
2K