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Is this proof for a linear differential eq correct purely mathematically

  1. Oct 29, 2007 #1
    Is this proof for a "linear differential eq" correct purely mathematically

    I wonder if this proof is correct purely mathematically
    look at (3) in the link, and you will se that they have done the following ...

    [tex] \int p(x)dx = \int p(x)dx +c[/tex]

    So they have put out the constant of integration before they have done the integration, can they really do that?

    http://www.bio.brandeis.edu/classes/biochem102/hndDiffEq.pdf
     
  2. jcsd
  3. Oct 29, 2007 #2
    Yes, since constant + constant = constant. They probably did that to emphasize that a constant will have to be worked out to fit some initial conditions.
     
  4. Oct 29, 2007 #3
    Yea it makes it much easier because then you don't need to think about constant of integration ... In my brain i can see that as mathematically correct if c=0 because e^0=1 ...

    I am fairly sure that you can't say c1+c=c2, for a value where c isn't cero, because the value from the integration (which gives c1) can just be the exactly correct value form that integration ...

    Sorry if i am concerned about stuff that don't matter, but for me it is important for my understanding ...

    Kindly Pellefant ...
     
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