- #1
ineedhelpnow
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$\sum_{n=0}^{\infty}\frac{2^n}{3^nn!}$
is this correct?
$\sum_{n=0}^{\infty}(\frac{2}{3})^n \frac{1}{n!}$
$\sum_{n=0}^{\infty}\frac{(x)^n}{n!}=e^x$
$x=2/3$
$e^x=e^{2/3}
is this correct?
$\sum_{n=0}^{\infty}(\frac{2}{3})^n \frac{1}{n!}$
$\sum_{n=0}^{\infty}\frac{(x)^n}{n!}=e^x$
$x=2/3$
$e^x=e^{2/3}