Is This the Sum of the Series? $\sum_{n=0}^{\infty}\frac{2^n}{3^nn!}$

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SUMMARY

The series $\sum_{n=0}^{\infty}\frac{2^n}{3^nn!}$ converges to $e^{2/3}$. This conclusion is derived from recognizing that the series can be rewritten as $\sum_{n=0}^{\infty}(\frac{2}{3})^n \frac{1}{n!}$, which matches the standard exponential series formula $\sum_{n=0}^{\infty}\frac{x^n}{n!}=e^x$ with $x$ set to $\frac{2}{3}$. Therefore, the evaluation of the series is confirmed to be correct.

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$\sum_{n=0}^{\infty}\frac{2^n}{3^nn!}$

is this correct?

$\sum_{n=0}^{\infty}(\frac{2}{3})^n \frac{1}{n!}$

$\sum_{n=0}^{\infty}\frac{(x)^n}{n!}=e^x$

$x=2/3$

$e^x=e^{2/3}
 
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Yes, that's correct. :D
 

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