Is This Wave Function Normalization Correct?

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The discussion focuses on the normalization of a wave function in quantum mechanics. A user seeks confirmation on their solution, noting that the parameter alpha should be included in the final answer. Participants point out that terms involving alpha cannot cancel out, as this would lead to an unsolvable equation. The user realizes their mistake in setting up the integrals and acknowledges the correction. The conversation concludes positively, with the user expressing gratitude and a renewed focus on studying.
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Homework Statement


http://www.ph.qmul.ac.uk/~phy319/problems/problems1.doc"
Question 2)b

The Attempt at a Solution



http://img685.imageshack.us/img685/9033/p270210111001.jpg

Is this correct?

Thanks!
 
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No. The parameter \alpha should appear in the answer. Your set-up looks fine, though.
 
vela said:
No. The parameter \alpha should appear in the answer. Your set-up looks fine, though.

But once we take out the infinity terms after the integral, we're left with the \alpha terms, one is + and one is -, so they cancel.

What is it I'm doing wrong here?

Thanks!
 
They can't cancel or else you'd be left with N2x0=1, which has no solution. Recheck the sign on each term.
 
I can't seem to find the problem, anyone care to take a look?

The only reason I can think of is the original way I set up the integrals, and whether I add them or subtract them!
 
\left[\frac{1}{-2\alpha}e^{-2\alpha x}\right]^\infty_0 \ne -\frac{1}{2\alpha}
 
vela said:
\left[\frac{1}{-2\alpha}e^{-2\alpha x}\right]^\infty_0 \ne -\frac{1}{2\alpha}

Ahhhhhh, I see now, thank you VERY much! :) Let the studying continue!
 

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