Is V_{eff} truly the density of effective action in QFT?

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ndung200790
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Please teach me this:
Why do we not call V[itex]_{eff}[/itex]=[itex]\Gamma_{eff}[/itex]/VT (where [itex]\Gamma[/itex][itex]_{eff}[/itex] is the effective action, VT is spacetime volume) being density of effective action of field?
Thank you very much in advance.
 
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I have just known(from Schoeder's QFT book) that V[itex]_{eff}[/itex]=v[itex]_{0}[/itex]([itex]\Phi[/itex][itex]_{cl}[/itex])[itex]\Phi[/itex][itex]^{4}_{cl}[/itex].Then this must be called effective potential,because it relates with interaction Phi-4(this case is an example) but must not be called density of action.Is that correct?