Is XeO2F4 in the D4h Point Group?

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SUMMARY

The compound XeO2F4 is correctly assigned to the D4h point group due to its symmetry elements, which include 1 C4 axis, 4 C2 axes, 4 σv planes, and 1 σh plane. This is analogous to XeF4, which also exhibits D4h symmetry. However, the discussion highlights that the octahedral (Oh) point group requires all six substituents on the central atom to be identical, which is not the case for XeO2F4. The presence of C3 axes in octahedral symmetry further differentiates it from D4h.

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Homework Statement


Had this question on a test today and now I'm having second thoughts. We were asked to assign the point group of symmetry for the compound XeO2F4.

Homework Equations


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The Attempt at a Solution


I had initially thought that it fell under D4h because it contains 1 C4 axis, 4 C2 axes, 4 σv planes and 1 σh plane. I know that the compound XeF4 is D4h and my rationale for assigning D4h to XeO2F4 was that it is identical to XeF4 except that instead of 2 lone pairs on the Xe there are 2 double bonded O's.

However, is the correct assignment for XeO2F4 octahedron (Oh)? It is a octahedral shape according to VSEPR but I'm not sure if all 6 substituents on the central atom have to be identical on Oh point groups.

Can someone please shed some light on this?

Cheers!
 
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ochemnerd said:

Homework Statement


Had this question on a test today and now I'm having second thoughts. We were asked to assign the point group of symmetry for the compound XeO2F4.

Homework Equations


None


The Attempt at a Solution


I had initially thought that it fell under D4h because it contains 1 C4 axis, 4 C2 axes, 4 σv planes and 1 σh plane. I know that the compound XeF4 is D4h and my rationale for assigning D4h to XeO2F4 was that it is identical to XeF4 except that instead of 2 lone pairs on the Xe there are 2 double bonded O's.

However, is the correct assignment for XeO2F4 octahedron (Oh)? It is a octahedral shape according to VSEPR but I'm not sure if all 6 substituents on the central atom have to be identical on Oh point groups.

Can someone please shed some light on this?

Cheers!

yes, all 6 have to be the same. Don't forget there are also C3 axes in octahedral symmetry, which are not present in your proposed structure.
 
Thanks for the clarification, sjb-2812!
I fail to see where the C3 axes would be though in a molecule of octahedral symmetry...
 

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