Isobar states decay probabilities

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SUMMARY

The discussion centers on the decay probabilities of the four isobar states of the Δ baryon: Δ++, Δ+, Δ0, and Δ-. All these states decay into a pion and a nucleon via the strong force. The participants conclude that isospin symmetry does not favor any particular decay channel among the four versions, indicating that the decay probabilities are indeed the same across these states. The role of Clebsch-Gordan coefficients in this context is also highlighted, emphasizing their relevance in understanding isospin symmetry.

PREREQUISITES
  • Understanding of baryon decay processes
  • Familiarity with isospin symmetry in particle physics
  • Knowledge of Clebsch-Gordan coefficients
  • Basic concepts of strong force interactions
NEXT STEPS
  • Research the role of isospin symmetry in particle decay
  • Study the application of Clebsch-Gordan coefficients in quantum mechanics
  • Explore the properties of the Δ baryon states in detail
  • Investigate the strong force and its implications for particle interactions
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Particle physicists, students of quantum mechanics, and anyone interested in baryon decay processes and isospin symmetry.

kelly0303
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Hello! Given an excited state of a nucleon, such as the ##\Delta## baryon (and here I mean all its 4 version ##\Delta^{++}##, ##\Delta^{+}##, ##\Delta^{0}##, ##\Delta^{-}##), the decay channel is (in this case) to a pion and a nucleon. I was wondering, is the decay probability the same for all 4 versions? I assume that they all decay through the strong force, and I don't see any quantum number that might favor one over the other, but I am not totally sure. Thank you!
 
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