"Isolated system model" can someone explain this to me?

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The discussion focuses on applying the isolated system model to analyze two connected objects with different masses, m1 and m2, in a pulley system. It emphasizes the importance of treating the objects separately to account for their distinct kinetic and potential energy changes, as their velocities and heights differ. The total changes in energy are combined, but the individual treatment allows for clearer calculations of forces and accelerations. This approach simplifies the analysis of the system's dynamics without losing accuracy. Understanding these principles is crucial for solving the homework problem effectively.
doneky
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Homework Statement


Two objects are connected by a light string passing over a light, frictionless pulley as shown in the figure below. The object of mass m1 = 4.80 kg is released from rest at a height h = 4.40 m above the table.
8-p-007.gif

(a) Using the isolated system model, determine the speed of the object of mass m2 = 3.00 kg just as the 4.80–kg object hits the table.
(b) Find the maximum height above the table to which the 3.00–kg object rises.

Homework Equations


KE = 1/2*mv^2
PE = mgh

The Attempt at a Solution


So, basically the answer is to combine the total changes in kinetic and potential energy, where nonconservative work equals zero.

But why? Why should these be treated separately instead of using a combined mass?
 
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doneky said:
But why? Why should these be treated separately instead of using a combined mass?
I do not understand your question. You are to consider the combined energies, no? That effectively combines the masses.
An approach that does not directly combine the masses is to work in terms of forces, treating each mass separately. They become connected then by using common values for tension and acceleration.
 
The reason they are being treated as separate bodies is because the energy for each object is different from the other. If you were to treat both object as same, it would be very difficult to calculate the velocity of the connected bodies, because the velocity of m1 is different from m2. Same is the case is for GPE. The height from the reference point is different for both objects.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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