Understanding ##SO(2)## as Isotropy Group for ##x \in R^3##

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SUMMARY

##SO(2)## is the isotropy group for a vector ##x \in R^3## when considering the action of ##SO(3)## on ##R^3## through rotations. The isotropy group consists of all elements that fix a specific point or vector, which in this case is the axis of rotation. Therefore, while ##SO(2)## represents rotations in a plane, it specifically fixes the line connecting the origin to the point ##x## when ##x## lies along the axis of rotation. This understanding clarifies the relationship between ##SO(2)## and the isotropy group in three-dimensional space.

PREREQUISITES
  • Understanding of group theory and group actions
  • Familiarity with the special orthogonal groups, specifically ##SO(2)## and ##SO(3)##
  • Basic knowledge of vector spaces, particularly ##R^3##
  • Concept of isotropy groups and fixed points in mathematical contexts
NEXT STEPS
  • Study the properties and definitions of special orthogonal groups, focusing on ##SO(3)##
  • Explore the concept of group actions and how they apply to vector spaces
  • Investigate the relationship between rotations and fixed points in higher-dimensional spaces
  • Learn about isomorphisms in group theory, particularly between ##SO(2)## and subgroups of ##SO(3)##
USEFUL FOR

Mathematicians, physicists, and students studying group theory, particularly those interested in the geometric interpretations of rotations and isotropy in three-dimensional space.

Silviu
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Hello! I am not sure I understand why ##SO(2)## is the isotropy group for ##x \in R^3##. If I understood it well, the isotropy group contains all the elements such that ##gx=x##. But this is not the case for ##SO(2)## as this group represents rotations in a plane, so unless x is the axis of rotation, x will be changed. What am I getting wrong here? Thank you!
 
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I am not sure of your context, but one interpretation is that ##x## represents the line (or vector) that connects the origin to ##x## considered as a point.
 
Silviu said:
Hello! I am not sure I understand why ##SO(2)## is the isotropy group for ##x \in R^3##. If I understood it well, the isotropy group contains all the elements such that ##gx=x##. But this is not the case for ##SO(2)## as this group represents rotations in a plane, so unless x is the axis of rotation, x will be changed. What am I getting wrong here? Thank you!
If I understand your question correctly, you must first have a group action defined, after which you determine the subgroup that fixes a given element.
 
If you mean the action of ##SO(3)## on ##R^3## by rotations then any rotation fixes its axis of rotation. The subgroup of rotations with a given axis is isomorphic to ##SO(2)##
 

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