I've never felt dumber: me understand Fibonacci identity.

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SUMMARY

The discussion centers on the Fibonacci identity, specifically the relationship between Fibonacci numbers and a sequence defined by E(n) = E(n-1) + E(n-2). The identity F(a+b+1) = F(a+1)F(b+1) + F(a)F(b) is derived from the properties of Fibonacci numbers, where E(0) and E(1) are defined as two consecutive Fibonacci numbers. The confusion arises from the transition between the definitions and the application of the identity, highlighting the complexity of understanding Fibonacci sequences in mathematical contexts.

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moe darklight
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This is crazy. I have no idea what the textbook is saying at the end.

if we have E(0)=A, E(1)=B, And E(n)=E(n-1)+E(n-2); then E(n)=F(n-1)A+F(n)B

(Where F(n) denotes a Fibonacci number.)

So far, so good. Then this flies at me out of nowhere:

We can start with two consecutive Fibonacci numbers A=F(a) and B=F(a+1). Then the sequence E(n) is just the Fibonacci sequence shifted to the left (agreed). Hence we get the following identity:

F(a+b+1)=F(a+1)F(b+1)+F(a)F(b)

We do?? Where the hell did that come from?

I've never stared at something for so long without having the slightest clue what is going on. I held up the whole class today for like 20 minutes, and it seemed to make sense when the prof explained it . . . but now I look at it again, and whatever I learned, I un-leaned. Ugh, I'm so frustrated.
 
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E(n)=F(n-1)A+F(n)B

E(n)=F(n-1)E(0)+F(n)E(1)

E(n+1)=F(n)E(0)+F(n+1)E(1)

and since E(n)=F(b+n) (by definition),

F(b+n+1)=F(n)F(b)+F(n+1)F(b+1)
 
:rolleyes: of course. Thanks.
 

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