Graduate J-aggregation and H-aggregation differences

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J-aggregates exhibit a red shift in their optical spectrum due to their lower energy states and lattice structure that restricts electron movement. In contrast, H-aggregates show a blue shift because their higher energy states allow for greater electron mobility and absorption of higher-energy photons. The fundamental difference in energy levels between J-aggregates and H-aggregates is key to their distinct optical properties. Additionally, J-aggregates cannot be transformed into H-aggregates, as their lower energy states prevent such a transition. Understanding these differences is crucial for applications in photonics and materials science.
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Why J-aggregation has red shift and H-aggregation has blue shift what is the physics behind it? And the second question is does J-aggregate can makes with another J-aggregate H-aggregate?? (I'm new in this topic)
 
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The difference in the energy levels of J-aggregates and H-aggregates is due to the fact that the J-aggregates are composed of molecules with lower energy states than those of the H-aggregates. In J-aggregates, the molecules form a lattice structure which restricts the movement of electrons, resulting in a red-shift in their optical spectrum. In H-aggregates, the molecules have higher energy states, allowing them to move more freely and absorb higher-energy photons, resulting in a blue-shift in their optical spectrum.No, J-aggregates cannot be used to create H-aggregates. The molecules in J-aggregates have lower energy states than those of the H-aggregates, and thus cannot be used to create an H-aggregate.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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