Java Java- Set hasDigit to true if the 3-character passCode contains a digit.

[dellmac]

Been working this problem for hours and can't seem to get it right. Any assistance would be greatly appreciated!

Note: Green colored text is the editable text

public class CheckingPasscodes {
public static void main (String [] args) {
boolean hasDigit = false;
String passCode = "";
int valid = 0;

passCode = "abc";

if (passCode.equals(Character.isDigit(passCode.length()))) {
hasDigit = true;
}

if (hasDigit) {
System.out.println("Has a digit.");
}
else {
System.out.println("Has no digit.");
}

return;
}
}

 

[dellmac]

So I just got it. I believe I used the long way though; not sure if there is an easier way:

if (Character.isDigit(passCode.charAt(0))) {
hasDigit = true;
}
if (Character.isDigit(passCode.charAt(1))) {
hasDigit = true;
}
if (Character.isDigit(passCode.charAt(2))) {
hasDigit = true;
}

 

[I like Serena]

So I just got it. I believe I used the long way though; not sure if there is an easier way:

if (Character.isDigit(passCode.charAt(0))) {
hasDigit = true;
}
if (Character.isDigit(passCode.charAt(1))) {
hasDigit = true;
}
if (Character.isDigit(passCode.charAt(2))) {
hasDigit = true;
}

Hi dellmac! (Smile)

That looks like the right direction.
But suppose the passCode is not length 3...
In other words, you need a loop:

for (int i = 0; i < passCode.length(); ++i) {
    if (Character.isDigit(passCode.charAt(i))) {
        hasDigit = true;
    }
}