Jump Physics: Calculating Flea's Speed, Height & Acceleration

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The discussion focuses on calculating a flea's jump physics, specifically its acceleration, height, and the duration of the acceleration phase. To determine the flea's acceleration, the "velocity-squared" equation is recommended, assuming the flea starts from rest. Once the acceleration is known, the time to reach a takeoff speed of 1.1 m/s can be calculated. The height of the jump can be found using the same equation, considering gravity as the only force acting on the flea once airborne. The conversation emphasizes the importance of unit compatibility and the impact of air resistance, which is ignored in these calculations.
Robdog
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Homework Statement



When jumping, a flea reaches a takeoff speed of 1.1 over a distance of 0.49 .

How long does the acceleration phase last?
What is the flea's acceleration during the jump phase?
If the flea jumps straight up, how high will it go? (Ignore air resistance for this problem; in reality, air resistance plays a large role, and the flea will not reach this height.)


Homework Equations



How do i get started

The Attempt at a Solution



None
 
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What are the units on your given numbers?
 
My bad .49mm and 1.1m/s
 
The flea cannot accelerate once he's off the ground, because there are no forces being applied. All you will be able to calculate is the average acceleration for the distance given. That's a simple d = vt, v = at, situation. Then the second part, I'm not too sure right now. There is something that's making me think that the acceleration will actually be negative. But I know that the flea is accelerating at more than 9.8, and the resultant is what the average acceleration you calculated is.
 
Robdog said:

Homework Statement



When jumping, a flea reaches a takeoff speed of 1.1 m/sec over a distance of 0.49 mm .

How long does the acceleration phase last?
What is the flea's acceleration during the jump phase?

Actually, it's easier from the information given to solve the second question first and then do the first one. (In textbook or exam questions with multiple parts, keep in mind that you are never *required* to answer the parts in the order given -- occasionally, it may even be impossible to do so...)

For the second question, you will want to use the "velocity-squared" equation: vf^2 = vi^2 + (2 a L) to solve for a ; we're assuming for the jump that the flea started from rest. [Don't forget to put your values in compatible units!] Once you know the (assumed) constant acceleration of the jumping flea, you can use the equation for velocity to find out how long it takes the flea to reach a speed of 1.1 m/sec. (The result will make it clear why it's so hard to catch fleas...)


If the flea jumps straight up, how high will it go? (Ignore air resistance for this problem; in reality, air resistance plays a large role, and the flea will not reach this height.)

Once the flea is in flight, gravity is taken to be the only force acting on it. You can again use the "velocity-squared" equation with the initial speed being vertically upward and the acceleration g due to gravity being vertically downward to find the vertical distance over which the flea's jump will take it. (What is the final velocity, that is, the velocity at the top of the jump?).

The only part I'm unclear on is whether they want you to take the vertical distance over which the flea decelerates during the jump and tack on the 0.49 mm of the acceleration phase (though that will turn out to be small in comparison).
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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