Kayaker paddling across a harbor

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Homework Help Overview

The problem involves a kayaker attempting to paddle across a 105 m wide harbor while contending with a tidal current flowing east at 1.5 m/s. The kayaker's paddling speed is 3.4 m/s, and the discussion focuses on determining the correct paddling direction to travel straight across and the time required to cross the harbor.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss using right triangle geometry to analyze the vectors involved in the problem. There are attempts to calculate the time to cross and the downstream distance due to the current, but confusion arises regarding the angle of paddling.

Discussion Status

Some participants have provided guidance on using vector addition to resolve the problem, suggesting that a right triangle can be employed to visualize the relationship between the kayaker's speed and the current. There is an acknowledgment of the complexity of the problem, with participants exploring different aspects without reaching a consensus.

Contextual Notes

Participants note that the kayaker will take longer than initially calculated to cross the harbor due to the influence of the current, indicating a need for further analysis of the vector components involved.

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Homework Statement



A kayaker needs to paddle north across a 105 m wide harbor. The tide is going out, creating a tidal current that flows to the east at 1.5 m/s. The kayaker can paddle with a speed of 3.4 m/s.

(a) In which direction should he paddle in order to travel straight across the harbor? (degrees west of north)

(b) How long will it take him to cross? (seconds)

Homework Equations



c^2= a^2 + b^2

The Attempt at a Solution



I divided 105m by 3.4 m/s to determine how long it would take to go straight across the harbor. Then I multiplied that number (30.88) by 1.5 m/s to get the distance he would have ended up downstream. 46.32m.

Then, I attempted to set up a right triangle and solve for the angle but that's where I got confused.
 
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magic-400 said:

Homework Statement



A kayaker needs to paddle north across a 105 m wide harbor. The tide is going out, creating a tidal current that flows to the east at 1.5 m/s. The kayaker can paddle with a speed of 3.4 m/s.

(a) In which direction should he paddle in order to travel straight across the harbor? (degrees west of north)

(b) How long will it take him to cross? (seconds)

Homework Equations



c^2= a^2 + b^2

The Attempt at a Solution



I divided 105m by 3.4 m/s to determine how long it would take to go straight across the harbor. Then I multiplied that number (30.88) by 1.5 m/s to get the distance he would have ended up downstream. 46.32m.

Then, I attempted to set up a right triangle and solve for the angle but that's where I got confused.

The kayaker will take longer than [30.88] that to cross the harbour, since he/she is not paddling directly towards the opposite side.
 
1. Homework Statement

A kayaker needs to paddle north across a 105 m wide harbor. The tide is going out, creating a tidal current that flows to the east at 1.5 m/s. The kayaker can paddle with a speed of 3.4 m/s.

(a) In which direction should he paddle in order to travel straight across the harbor? (degrees west of north)

(b) How long will it take him to cross? (seconds)

Then, I attempted to set up a right triangle and solve for the angle but that's where I got confused.

-----------------------------------------------------
Yes you can use a right triangle to solve the problem.
This is a vector problem and using a right triangle geometry is one of the methods.

Kayaker speed with direction is one vector.
The tide speed and direction is another vector.
You can do operations on this 2 vectors and in this example adding the two vectors.

The sum of the two vectors will result in the kayaker paddling straight across the habour.
 
What azizlwl said.

If still stuck post your attempt at the vector diagram.
 

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