KCL: Circuits & Current - Need Help?

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SUMMARY

The forum discussion centers on the application of Kirchhoff's Current Law (KCL) in analyzing a circuit involving multiple resistors. Specifically, at node Nd, the total current flowing out through resistors R3 and R4 is calculated to be 2 mA. The incoming currents from resistors R1 and R2 total 4 mA, leading to the conclusion that the current from resistor R5 (I5) must be -2 mA, indicating it flows from bottom to top. This analysis confirms the correct application of KCL in circuit analysis.

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  • Understanding of Kirchhoff's Current Law (KCL)
  • Basic knowledge of circuit components such as resistors
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  • Familiarity with current flow direction in electrical circuits
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In the given figure, at the node where R3 and R4 are connected (let us call this as Nd), the total current flowing out of the node through R3 and R4 is (4-2mA=2mA). Now there are two other paths joining at Nd. So the current from these two paths into the node Nd could be 4mA ( from R1 and R2 paths) and current from R5 path (let us call this as I5). Now applying KCL at node Nd, 4mA+I5=2mA , giving I5=-2mA, so I5 should flow from bottom to top.
 

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