Kinectic energy of a system of 2 objects

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It is possible to find the kinetic energy of a system of two objects moving at different constant speeds by calculating their individual kinetic energies and summing them. Alternatively, one can analyze the system from the reference frame of one object, treating the other as moving. While total momentum is conserved, kinetic energy is not, leading to different values depending on the reference frame. However, all frames agree on kinetic energy conservation during elastic collisions. The kinetic energy of the system can be expressed using the center of mass velocity and the relative velocities of the objects.
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is it possible to find kinetic energy of a system of 2 objects when they're both moving at 2 different constant speeds?

because In my textbook, they all assume that one stays at rest and another is moving.
 
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Either method works.

You could either calculate the kinetic energy of each object individually then sum to get the total kinetic energy (it wouldn't matter that the two objects are moving at different speeds because you are calculating them separately). You could also look at the situation from the reference frame of one of the objects, in which case only the other object is moving, and then the kinetic energy of that other object is the total kinetic energy of the system.

Even though total momentum is conserved, kinetic energy by itself is not conserved. This means that different reference frames might show different amounts of kinetic energy in a system.

However all reference frames will agree that kinetic energy is conserved in an elastic collision.
 
It depends on what energy you actually want to measure. If you want to measure the kinetic energy of one object with respect to the other, then you can consider one of them stationary and use their relative velocity to find the kinetic energy. If on the other hand you want to find the kinetic energy of the objects with respect to some fixed point ,just add their kinetic energy with respect to that point. In general the two values you obtain are different.
 
Vorde said:
Either method works.

You could either calculate the kinetic energy of each object individually then sum to get the total kinetic energy (it wouldn't matter that the two objects are moving at different speeds because you are calculating them separately). You could also look at the situation from the reference frame of one of the objects, in which case only the other object is moving, and then the kinetic energy of that other object is the total kinetic energy of the system.

Even though total momentum is conserved, kinetic energy by itself is not conserved. This means that different reference frames might show different amounts of kinetic energy in a system.

However all reference frames will agree that kinetic energy is conserved in an elastic collision.

But how you calculate the velocity of the center of mass?

THe formula of K of a system is : Ksys = (K of COM) +K(the object relative to the COM)
 
daivinhtran said:
But how you calculate the velocity of the center of mass?

THe formula of K of a system is : Ksys = (K of COM) +K(the object relative to the COM)

R=\frac{1}{M}\sum_i m_i r_i

\frac{dR}{dt}=\frac{d}{dt}\frac{1}{M}\sum_i m_i r_i=\frac{1}{M}\sum_i m_i \frac{dr_i}{dt}=\frac{1}{M}\sum_i p_i
 
bp_psy said:
R=\frac{1}{M}\sum_i m_i r_i

\frac{dR}{dt}=\frac{d}{dt}\frac{1}{M}\sum_i m_i r_i=\frac{1}{M}\sum_i m_i \frac{dr_i}{dt}=\frac{1}{M}\sum_i p_i

THANKS BUDDYYYYY :d :d
 
I do not have a good working knowledge of physics yet. I tried to piece this together but after researching this, I couldn’t figure out the correct laws of physics to combine to develop a formula to answer this question. Ex. 1 - A moving object impacts a static object at a constant velocity. Ex. 2 - A moving object impacts a static object at the same velocity but is accelerating at the moment of impact. Assuming the mass of the objects is the same and the velocity at the moment of impact...

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