Kinematics - Acceleration in Two Dimensions. Stuck.

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Homework Help Overview

The discussion revolves around a kinematics problem involving the average acceleration of a hockey puck that rebounds from a board. The original poster presents initial conditions, including the initial and final velocities, and attempts to calculate the average acceleration using vector components and the cosine law.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to use the cosine law and vector components to find the average acceleration but encounters discrepancies in their calculations. They express confusion over the correct application of sine and cosine in their vector component calculations.

Discussion Status

Some participants provide feedback on the original poster's use of sine and cosine, suggesting that there may be errors in their approach. The conversation indicates a lack of consensus on how to correctly apply the equations, with participants questioning the original poster's understanding of the textbook examples.

Contextual Notes

The original poster references a specific textbook, Nelson Physics 12, and expresses confusion regarding the application of concepts from the text to their problem. There is mention of a related example in the textbook that is causing additional confusion.

mattstjean
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Hi, I am also having trouble with the hockey puck question.

A hockey puck rebounds from a board as shown in my diagram. The puck is in contact with the board for 2.5 ms. Determine avg acceleration of the puck over the interval.

Vi = 26 m/s Vf = 21 m/s

I tried the cosine law but I keep getting 44 m/s and not 18. I don't understand how you guys got 18 m/s. I've plugged it in at least 100 times as
<br /> v_t = \sqrt{v_1^2 + v_2^2 - 2(v_1)(v_2)cos136}<br /> = \sqrt{26^2 + 21^2 - 2(26)(21)cos136}<br /> =44<br /> =

Because that wasn't working I then tried Vector Components and I can't get that to work either. I did:
<br /> V_x = V_B sin \theta + (-V_A cos \beta ) <br /> = 21 sin(22) - 26 cos(22)<br /> =-16<br />

and

<br /> V_y = V_B cos \theta + (-V_A sin \beta ) <br /> = 21 (cos22) + 26(sin22)<br /> = 29 <br />

I then tried to figure out
<br /> \Delta V ^2= \Delta V_x ^2 + \Delta V_y^2 <br /> = sqrt{16^2 + 29^2}<br /> = 33<br />

Using that I tried to get the average acceleration by:

<br /> A_av = \Delta V / \Delta T<br /> <br /> A_av = 33 / 2.5x10^-3<br /> A_av = 13.2x10^3<br />
and to find the angle I tried to do :

<br /> \phi = tan^-1 = 16/29<br /> \phi = 29degrees<br />

However, the answer in my book says that the average acceleration is 7.3x10^3 [7.5degrees North of West]
Any help would be amazingly appreciated. Thanks.
 

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mattstjean said:
Because that wasn't working I then tried Vector Components and I can't get that to work either. I did:
<br /> V_x = V_B sin \theta + (-V_A cos \beta ) <br /> = 21 sin(22) - 26 cos(22)<br /> =-16<br />
You have a mix of sine and cosine. Only one is correct.
and

<br /> V_y = V_B cos \theta + (-V_A sin \beta ) <br /> = 21 (cos22) + 26(sin22)<br /> = 29 <br />
Again, a mix of sine and cosine.

Redo this.
 
Doc Al said:
You have a mix of sine and cosine. Only one is correct.

Again, a mix of sine and cosine.

Redo this.

I don't know how to redo it. In my textbook it used them both together in the y and x component vector subtraction. I took the equations right out of my text, Nelson Physics 12.
 
mattstjean said:
I don't know how to redo it. In my textbook it used them both together in the y and x component vector subtraction. I took the equations right out of my text, Nelson Physics 12.
I'm not sure what equations you are talking about.

Do this: What's the x-component of Vi? The x-component of Vf?
 
I have the same book and I am stuck on the example on right before the quesion box you asked about. can you please explain the lawn mower example in pg 28. I AM VERY CONFUSED
 

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