hi im having some trouble with the question below, was hoping maybe someone could talk me through it? A ball is thrown from a point on an incline of 16 degrees with an initial velocity of 19m/s and at an angle of 49 degrees to the incline. How far up the plane will the ball strike measured from its initial position? so far i have resolved the velocity into its x and y directions Ux = 8.03m/s Uy = 17.22m/s So - Sy = Uy*t-(0.5gt^2) Sx = Ux*t Now i get stuck with the rest, i have to: Express the height of the incline, Sp in terms of time, t Sp = ____ xt At the point of impact, y = Sp, find t: t = ____ s Now find Sx and Sp Sx = ____ m Sp = ____ m Therefore, the distance up the incline from the point where the ball was released is: Sball = _____ m i would appreciate any help people can offer me with this as i understand its not that difficult but just cant grasp it. thanks les.