hi im having some trouble with the question below, was hoping maybe someone could talk me through it?(adsbygoogle = window.adsbygoogle || []).push({});

A ball is thrown from a point on an incline of 16 degrees with an initial velocity of 19m/s and at an angle of 49 degrees to the incline. How far up the plane will the ball strike measured from its initial position?

so far i have resolved the velocity into its x and y directions

Ux = 8.03m/s

Uy = 17.22m/s

So - Sy = Uy*t-(0.5gt^2)

Sx = Ux*t

Now i get stuck with the rest, i have to:

Express the height of the incline, Sp in terms of time, t

Sp = ____ xt

At the point of impact, y = Sp, find t:

t = ____ s

Now find Sx and Sp

Sx = ____ m

Sp = ____ m

Therefore, the distance up the incline from the point where the ball was released is:

Sball = _____ m

i would appreciate any help people can offer me with this as i understand its not that difficult but just cant grasp it.

thanks les.

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# Kinematics ball throwing question

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