Kinematics Constant Acceleration

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SUMMARY

The discussion centers on a kinematics problem involving constant acceleration, where a car accelerates at 3.2 m/s² from rest while a truck travels at a constant speed of 20 m/s. The key equations used include D1 = V1t + 1/2at² for the car's distance and D = vt for the truck. The solution involves determining the distance until the car overtakes the truck and calculating the car's speed at that moment. The final resolution of the problem was achieved by correctly manipulating the equations to solve for D.

PREREQUISITES
  • Understanding of kinematic equations, specifically D = Vt + 1/2at²
  • Knowledge of constant acceleration concepts in physics
  • Ability to manipulate algebraic equations for problem-solving
  • Familiarity with basic units of measurement in physics (meters, seconds)
NEXT STEPS
  • Study the derivation and application of kinematic equations in different scenarios
  • Learn about graphical representations of motion and acceleration
  • Explore real-world applications of constant acceleration in automotive engineering
  • Investigate the effects of varying acceleration on motion dynamics
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Students studying physics, particularly those focusing on kinematics, as well as educators looking for practical examples of constant acceleration problems.

anubis01
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Homework Statement


The instant the traffic light turns green a car accelerats at 3.2 m/s^2. At the same instant a truck traveling at 20m/s overtakes the car.

a) How far until the car overtakes the truck

b)How fast is the car traveling when it overtakes the truck.


Homework Equations


V1c=o VT=20.0 m/s
D=? D=?
a1=3.2m/s^2 t2=D/20
t1=? a=0 m/s^2

The Attempt at a Solution


D1=V1t +1/2at^2
=0+1.6(D/20)^2
=(1.6D^2/400)
The last part is where I am stuck. I don't know how to properly square a number/number.
 
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Try dividing both sides of the equation by D.
 
alright I figured it out, thanks for the help. Its much appreciated.
 

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