Kinematics in Two Dimension-Niagra falls

  • Thread starter Thread starter pstfleur
  • Start date Start date
  • Tags Tags
    Kinematics
Click For Summary
SUMMARY

The discussion focuses on calculating the vertical distance below the edge of Niagara Falls where the water's velocity vector points downward at a 75-degree angle. The initial horizontal speed of the water is 2.7 m/s, with no horizontal acceleration. The initial vertical velocity is assumed to be 0 m/s, while the vertical acceleration due to gravity is 9.8 m/s². To determine the vertical distance, the y-component of the velocity must be calculated to achieve the desired angle of 75 degrees with the known x-component.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of vector components and angles
  • Familiarity with gravitational acceleration (9.8 m/s²)
  • Basic algebra for solving equations
NEXT STEPS
  • Calculate the vertical distance using kinematic equations
  • Learn about projectile motion and its components
  • Explore the concept of velocity vectors and their angles
  • Study the effects of gravity on falling objects
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding the dynamics of falling objects in two-dimensional motion.

pstfleur
Messages
29
Reaction score
0
Kinematics in Two Dimension-Niagra falls(not solved)

1. Suppose the water at the top of Niagra falls has a horizontal speed of 2.7 m/s just before it cascades over the edge of the falls. At what vertical distance below the edge does the velocity vector of the water point downward at a 75 degree angle below the horizontal.



3. Ok so i know the intial and final velocity in the x direction is equal to 2.7m/s with a 0 acceleration.. when it falls I assume that its initial velocity in the y direction is 0?(let me know if I am wrong here), and the acceleration to that is 9.8...now i need to figure out the time to get my Vfy, but I think i need My final position in order to calculate time. please help.
 
Last edited:
Physics news on Phys.org
Yes, you'd assume the y component of velocity is zero as it drops initially. What is key here is the resultant velocity vector being at 75 degrees below horizontal. You know the x component so you need to find the y component that will give that angle to the resultant. Then you can find the vertical distance.
 

Similar threads

Replies
18
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
22
Views
3K
Replies
27
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
16
Views
1K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K