# Kinematics of the human canon fly zaccini

as a human canon fly zaccini flied a distance of 53 meter in 1940 ( still record )
his velocity as he leave the cannon is 24,5 m/s in a angle a with thw horizontalplane

a) what is the angle ? ( 31,2 )
b) find the highest point during the record ( 8,04m)

can you set up theese tasks ?

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as a human canon fly zaccini flied a distance of 53 meter in 1940 ( still record )
his velocity as he leave the cannon is 24,5 m/s in a angle a with thw horizontalplane

a) what is the angle ? ( 31,2 )
b) find the highest point during the record ( 8,04m)

can you set up theese tasks ?
Do anyone know the formula ?

x = v0*cos(a)*t
y = v0*sin(a)*t - 1/2*gt^2
since when x = 53 m, y = 0
v0*sin(a)*t - 1/2*gt^2 = 0
so t = 2v0*sin(a)/g
then x = v0*cos(a)*2v0*sin(a)/g = v0^2*sin(2a)/g
sin(2a) = g*x/v0^2
plug known values and get a = 30 degrees (not 31.2 (?))
then we can find t.
highest: find y when t' = t/2

butI dont get it :(
g*x/vo^2 I get 0,88 ? ( 9,8*53/24,2^2)

And the reason for 30 degress was that I did put in wrong velocity It should be 24,2m/s