A stone is dropped off a cliff of height h. At the same time, a second stone is throne straight upward from the base of a cliff with an initial velocity v. Assuming that the second rock is thrown hard enough at what time t will the two stones meet.
Uniform acceleration equations
The Attempt at a Solution
I tried a few different things, and nothing worked. I don't have anything written down right now though.
I just wrote Δd = v1Δt + 1/2gΔt2, for both stones, substituting Δd for x in one of the equations, and h - x in the other.
So, I just had x = 1/2gΔt2 and h - x = v1Δt + 1/2gΔt2
I tried combining them, but I got to a point where I didn't think I could do anything else with it, and it just felt wrong.
Am I thinking about it wrong?