1. The problem statement, all variables and given/known data When the frequency of light incident on a metallic plate is doubled, the K.E. of the emitted photoelectrons will be? 2. Relevant equations The answer should be either doubled or increased but more than double of the previous kinetic energy 3. The attempt at a solution λ= h/ √2mK.E. therefore, 1/v= h/c*√2mK.E.