Kinetic to Elastic Potential Energy

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SUMMARY

The discussion focuses on calculating the spring constant of a bumper using kinetic energy and spring compression data. A car with 40,000 J of kinetic energy traveling at 7.0 m/s compresses a spring 0.30 m upon impact. The spring constant is calculated using the formula k = 2KE/s², resulting in a value of approximately 8.9x105 N/m. Assumptions include perfect energy conservation and no additional compressions in the system during the impact.

PREREQUISITES
  • Understanding of kinetic energy (KE) and elastic potential energy (PE) concepts
  • Familiarity with the spring constant (k) and Hooke's Law
  • Basic algebra for manipulating equations
  • Knowledge of energy conservation principles
NEXT STEPS
  • Study the derivation of Hooke's Law and its applications in mechanical systems
  • Explore energy conservation in elastic collisions
  • Learn about the behavior of springs under different loading conditions
  • Investigate real-world applications of spring constants in automotive safety features
USEFUL FOR

Students in physics, mechanical engineers, and automotive safety designers will benefit from this discussion, particularly those interested in energy transfer and spring mechanics.

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Homework Statement


A moving car has 40,000 J of kinetic energy while moving at a speed of 7.0 m/s. A spring-loaded automobile bumper compresses 0.30 m when the car hits a wall and stops. What can you learn about the bumper’s spring using this information? Answer quantitatively and list the assumptions that you made.

KE = 40,000 J
v_i = 7.0 m/s
v_f = 0 m/s
\vec s = 0.30 m

Homework Equations


KE = Elastic PE = \frac {1}{2} k {\vec s}^2 \Rightarrow k = \frac {2KE}{{\vec s}^2}

The Attempt at a Solution


k = \frac {2(40,000 J)}{(0.30 m)^2} = 888888.88 N/m \sim 8.9x10^5 N/m

I learned that the bumper's spring has a constant of 8.9x10^5 N/m. I assumed that energy wasn't lost from the point when the car had 40,000 J of KE to when it impacted the wall, i.e. the energy was perfectly conserved.

Thank-you
 
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Looks ok. Not sure it is necessary to require that work is perfectly conserved, nor is it the time up to the impact that's of interest. Even if the spring failed to re-expand when released, the answer would be the same. Might be more relevant to mention that you assume there are no compressions anywhere else in the system (car or wall) during the impact.
 
Thank-you haruspex.
 

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