Kirchhoff's law - Simultanious Equations - Question

[College_Noobie]

When Kirchhoff's law are applied to a particular electrical circuit the current I^1 & I^2 are connected by the equations;

27 = 1.5 I^1 + 8 (I^1 - I^2)
-26 = 2 I^2 - 8 (I^1 - I^2)

Please show working out =)

 

[HallsofIvy]

Why was this posted under "differential equations"?

Taking I^1= x and I^2= y because your notation was confusing me, you have
27= 1.5x+ 8(x-y)= 1.5x+ 8x- 8y= 9.5x- 8y and
-26= 2y- 8(x- y)= 2y- 8x+ 8y= 10y- 8x.

That is you want to solve the equations 8x- 10y= 26 and 9.5x- 8y= 27.

You might try multiplying the first equation by 4 (so you get -40y) and the second equation by -5 (so you get +40y) and adding those equations to eliminate y.

No, I'm not going to "show working out". I am going to assume that you are capable of doing the basic algebra here yourself! The practice will do you good.

 

[College_Noobie]

sorry about the place of posting i was unable to work out which of the mathimatics sections it should go under.

and sorry about the "I to the power of 1 and I to the power of 2"

dont worry about the working out =) i will be able to carry on from there

Thanks