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## Homework Statement

Actually, the main question is to find out the potential difference between the points 'A' and 'D'.

The cell with emf 'E' has not been shown in the main question, but I have assumed it to be connected between 'A' and 'D'. Each resistor is of 1 Ohm.

**2. The attempt at a solution**

While solving the question, I applied Kirchhoff's Laws

Let 'I' be the current and let 'I

_{1}' be the current through the branch QR.

Since the total resistance offered by the branches (QR, PS, TU) is same (One ohm) , the currents through them will also be the same.

Assuming E > 3 V ( where 'E' is the emf of the cell)

Applying Kirchhoff's Current Law,

I = 3 I

_{1}

Applying KVL to the loop BAPQRDCB,

Δ V = 0

So, I(1) + I

_{1}(1) + 3 = E ....(1)

Similarly,

When KVL is applied to the loop BAPSDCB,

I(1) + I

_{1}(1) + 2 = E ....(2)

(1) = (2), as E = E,

Which, on solving, gives

__2 = 3!__Where did I go wrong?

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