MHB Kyra's question at Yahoo Answers regarding linear difference equations

  • Thread starter Thread starter MarkFL
  • Start date Start date
  • Tags Tags
    Difference Linear
Click For Summary
If the second differences of a sequence are constant, the function is quadratic. This is derived from the inhomogeneous linear recurrence relation, which leads to a characteristic equation with a triple root. The closed form of the sequence can be expressed as a quadratic function. Therefore, the correct answer to the question posed is option B, quadratic. Further discussions on difference equations can be found on dedicated math forums.
MarkFL
Gold Member
MHB
Messages
13,284
Reaction score
12
Here is the question:

Math hmk help asap?

help.,, Homework .,, thank you :))

If the second differences are the same, then the function is:
A. linear
B. quadratic
C. exponential
D. neither

Here is a link to the question:

Math hmk help asap? - Yahoo! Answers

I have posted a link there to this topic so the Op can find my response.
 
Mathematics news on Phys.org
Re: Kyra's question at Yahoo! Answers regardin linear difference equations

Hello Kyra,

Let the $n$th term of the sequence be given by $A_n$. If the second difference is constant, then we may state:

$$\left(A_{n}-A_{n-1} \right)-\left(A_{n-1}-A_{n-2} \right)=k$$ where $$0\ne k\in\mathbb{R}$$

Combining like terms, we may arrange this as the inhomogeneous linear recurrence:

(1) $$A_{n}=2A_{n-1}-A_{n-2}+k$$

We may increase the indices by 1, to prepare for symbolic differencing:

(2) $$A_{n+1}=2A_{n}-A_{n-1}+k$$

Subtracting (1) from (2), we obtain the homogeneous linear recurrence:

$$A_{n+1}=3A_{n}-3A_{n-1}+A_{n-2}$$

The characteristic equation is then:

$$r^3-3r^2+3r-1=(r-1)^3=0$$

Since the root $r=1$ is of multiplcity 3, we know the closed form will be:

$$A_n=k_1+k_2n+k_3n^2$$

We see then that the closed form is quadratic, hence B is the answer.

To Kyra and any other guest viewing this topic, I invite and encourage you to post other difference equation problems in our http://www.mathhelpboards.com/f15/ forum.

Best Regards,

Mark.
 
Thread 'Erroneously  finding discrepancy in transpose rule'
Obviously, there is something elementary I am missing here. To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix in the real plane; taking the transpose we get which then corresponds to a-bi...

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
4K
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K