The discussion centers on calculating the frequency of an AC voltage source connected to a 50.0 mH inductor with a voltage of 24.0V and a current of 0.60A. The key formula used is impedance (z), defined as z = V/I, which relates voltage (V), current (I), and the inductive reactance (Lω). The correct frequency can be derived using the relationship f = ω/(2π), leading to the conclusion that the frequency is 60Hz based on the provided parameters.
PREREQUISITESElectrical engineers, students studying AC circuit theory, and anyone involved in designing or analyzing inductive circuits will benefit from this discussion.
You can do better than this. How will you bring in L, E and i? Think impedance.-Aladdin- said:My Work so far ! :
f = w/2pi.
But here we have L , E and i.
Any help will be welcomed.
kuruman said:You can do better than this. How will you bring in L, E and i? Think impedance.
-Aladdin- said:So,impedance is : z=Lw = L*2pi*f ...
A guess , z = V/I = E/i ! but V(max)/I(max)
kuruman said:If z = V/I, can you relate ω to V and I?
kuruman said:Correct.