Laplacian cylindrical coordinates

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SUMMARY

The Laplacian in cylindrical coordinates is expressed as \Delta=\frac{\partial^2}{\partial \rho^2}+\frac{1}{\rho}\frac{\partial}{\partial \rho}+\frac{1}{\rho^2}\frac{\partial^2}{\partial \varphi^2}+\frac{\partial^2}{\partial z^2}. When analyzing a spherically symmetric function f(r), the Laplacian simplifies to \Delta f(r)=\frac{d^2}{dr^2}f(r)+\frac{2}{r}\frac{d}{dr}f(r). The confusion arises when substituting f(r) with f(\rho), particularly regarding the factor of 2. The correct interpretation is f(r)=f(\sqrt{\rho^2+z^2}), which resolves the discrepancy.

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LagrangeEuler
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Laplacian in cylindrical coordinates is defined by

\Delta=\frac{\partial^2}{\partial \rho^2}+\frac{1}{\rho}\frac{\partial}{\partial \rho}+\frac{1}{\rho^2}\frac{\partial^2}{\partial \varphi^2}+\frac{\partial^2}{\partial z^2}
I am confused. I I have spherical symmetric function f(r) then
\Delta f(r)=\frac{d^2}{dr^2}f(r)+\frac{2}{r}\frac{d}{dr}f(r)
If I worked on function ##f(r)## with Laplacian in cylindrical coordinates. I suppose that f(r)=f(\rho) but then factor ##2## is problem.
 
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I think it is ##f(r)=f(\sqrt{\rho^2+z^2})##.
 
Of course. Thanks.
 

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