There is a metal sphere which is cut and flattened at on one side and the flat side rests on an inclined surface. The figure is attatched please refer it. The weight of the sphere is W = 20*9.81 N . The sphere will tend to slide on the inclined surface as perceived. But the vetical wall on the left hand side prevents it from doing so and the sphere is in static equilibrium. The reactions generated at both the supports are R1 ( at vertical left wall) and R2 (at the inclined surface acting Normal to the surface) as shown. The working out of the Equilibrium Equations the reaction R2 at comes out to be 305.23 N ( We do not discuss about reaction R1 here as it is not of our interest) NOW THE REAL QUESTION : The Reaction to any force is generally (to our general perception or natural instinct) equal to the force or a fraction of the force if the force is acting at an angle to the support ( the sine or cosine term like Wsinθ or Wcosθ) But we never think of or perceive the reaction to EXCEED the Acting Force. However in the example above the Reaction R2 (R2 = 305.23 N) is much more than the ONLY ACTING FORCE i.e. THE WEIGHT of the sphere (W = 20*9.81 = 196.2 N) I've been wondering from WHERE does this EXTRA FORCE come from or WHAT GENERATES IT if the ONLY ACTING ( AVAILABLE SOURCE ) OF FORCE is THE WEIGHT i.e. ONLY 196.2 N. What happens and how does the reaction turn out to be greater than the apllied force. I couldnt figure out the actual REASON or PHYSICS behind this happening. Neither could I simply sit down satisfied with the Numerically correct answer and forgetting about the actual concept behind How the reaction turned out to be greater than the applied force. And What generated or developed this reaction which Exceeds the Force Applied. So can anyone please explain this phenomena as to How the reaction becomes greater than the applied force.