The discussion revolves around the laws of motion and circular motion, specifically focusing on a problem involving static friction and centripetal force in a system with a slider and a rod. Participants are attempting to analyze the forces acting on the slider when it is stationary relative to the rod.
Some participants are seeking clarification on the components of the forces involved and whether all relevant forces have been considered. There is an ongoing exploration of the problem, with hints and questions being raised about the correct approach to parts (ii) and (iii) of the problem.
There is mention of a specific answer (4.07 rad/s) that does not align with the calculations presented, indicating potential misunderstandings or miscalculations in the approach taken. Additionally, the thread has been noted as being older, with one participant referencing the inactivity of another contributor.
You have only considered one component of the centripetal force: the component that acts parallel to the inclined rod. What about the other component that acts perpendicular to the inclined rod?a150daysflood said:If it doesn't move, I assume the centripetal force= the static friction
Which is (cos30)mrw^2= (0.2)(sin60)9.81
But this doesn't give me the answer given which is 4.07rad/s. Can highlight where did I go wrong?
Hootenanny said:You have only considered one component of the centripetal force: the component that acts parallel to the inclined rod. What about the other component that acts perpendicular to the inclined rod?
@haha1234, this thread is about 2 years old and @Hootenanny is no longer active on PF.haha1234 said:Did I have anything wrong?
mrω2=μkmgcos30+mgtan60