Learn Hankel Transform & Application to Laplace Eq.

  • Context: Graduate 
  • Thread starter Thread starter Clausius2
  • Start date Start date
  • Tags Tags
    Transform
Click For Summary
SUMMARY

This discussion focuses on the Hankel Transform and its application to the Laplace Equation, specifically the operator L_m^2 defined as L_m^2=\frac{1}{r}\frac{\partial}{\partial r}\left(r\frac{\partial}{\partial r}\right)-\frac{m^2}{r^2}+\frac{\partial^2}{\partial z^2}. The solution to the equation L_m^2 f=0 is derived using a bipolar change of variables, resulting in a complex integral involving the Bessel function J_m(s\eta). Participants express challenges in transforming the differential operator under these variable changes, particularly with the second derivative.

PREREQUISITES
  • Understanding of differential equations, particularly the Laplace Equation.
  • Familiarity with Bessel functions and their properties.
  • Knowledge of variable transformations in calculus.
  • Basic grasp of integral transforms, specifically the Hankel Transform.
NEXT STEPS
  • Study the properties and applications of the Hankel Transform in solving differential equations.
  • Learn about the derivation and applications of Bessel functions, particularly J_m(s\eta).
  • Research techniques for performing variable changes in differential operators.
  • Explore advanced topics in the Laplace Equation and its solutions using integral transforms.
USEFUL FOR

Mathematicians, physicists, and engineers working with differential equations, particularly those interested in the applications of the Hankel Transform and Bessel functions in solving complex problems.

Clausius2
Science Advisor
Gold Member
Messages
1,433
Reaction score
7
Hey guys,

Do you have any advice of a place for learning about Hankel's Transform and its application to Laplace Equation?.

There are a couple of lines of a paper in which I am stuck on, I don't know how do they do this stuff:

Defining the operator [tex]L_m^2=\frac{1}{r}\frac{\partial}{\partial r}<br /> \left(r\frac{\partial}{\partial r}\right)-\frac{m^2}{r^2}+\frac{\partial^2}{\partial z^2}[/tex]

then the solution of [tex]L_m^2 f=0[/tex] under the bipolar change of variables [tex]r=2\eta/(\eta^2+\xi^2)[/tex] and [tex]z=2\xi/(\eta^2+\xi^2)[/tex] is given by:

[tex]f=(\xi^2+\eta^2)^{1/2}\int_0^\infty(A(s)sinh(s\xi)+B(s)cosh(s\xi))J_m(s\eta)ds[/tex]

I have tried to perform the change of variables in the differential operator, but it turns out to be the Hell when doing that for the second derivative. Any advice?

Thanks.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
2
Views
2K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 1 ·
Replies
1
Views
10K
  • · Replies 4 ·
Replies
4
Views
11K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K