Length of spin vector for spin-½ particle

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The discussion revolves around the calculation of the spin vector length for a spin-½ particle, with the initial answer provided as |S| = √3/2 * ħ. There is confusion regarding whether this value qualifies as angular momentum, as the question specifies it must be. Participants clarify that ħ indeed has the dimensions of angular momentum, suggesting that the original calculation may be valid. The conversation highlights the importance of understanding the relationship between spin and angular momentum in quantum mechanics. Ultimately, the clarification reinforces that spin-½ particles do possess angular momentum characteristics.
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Homework Statement
What's the length of a spin-½ spin vector in physical dimensions.
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My answer so far in |S| = √3 /2 *hbar but the question states it must be an angular momentum. Is this an angular momentum or am I missing something? Thanks
 
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##\hbar## has the dimensions of angular momentum.
 
I want to find the solution to the integral ##\theta = \int_0^{\theta}\frac{du}{\sqrt{(c-u^2 +2u^3)}}## I can see that ##\frac{d^2u}{d\theta^2} = A +Bu+Cu^2## is a Weierstrass elliptic function, which can be generated from ##\Large(\normalsize\frac{du}{d\theta}\Large)\normalsize^2 = c-u^2 +2u^3## (A = 0, B=-1, C=3) So does this make my integral an elliptic integral? I haven't been able to find a table of integrals anywhere which contains an integral of this form so I'm a bit stuck. TerryW

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