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Length on vibrating section of violin

  1. Oct 26, 2013 #1
    1. The problem statement, all variables and given/known data
    A particularly beautiful note reaching your ear from a rare Stradivarius violin has a wavelength of 39.1 cm. The room is slightly warm, so the speed of sound is 344 m/s.

    If the string's linear density is 0.560g/m and the tension is 160N , how long is the vibrating section of the violin string?

    2. Relevant equations
    f=c/wavelength
    f=sqrt(F/(m/L))/(2L)

    3. The attempt at a solution
    frequency = (344m/s) /(.391m) = 879Hz
    879=sqrt(160/(.000560/L))/(2L)
    i converted .560g/m to .000560kg/m because force is in Newtons
    did algebra and got that length is 10.81m, which is wrong.
    Not sure what I did wrong though.
     
  2. jcsd
  3. Oct 26, 2013 #2

    haruspex

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    Looks like an arithmetic error. Can't tell what you did wrong if you don't post all your work.
     
  4. Oct 26, 2013 #3

    gneill

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    You were given the linear density of the string, not its entire mass. So no need to divide it by L in your velocity expression.
     
  5. Oct 26, 2013 #4
    yes i was given the linear density, so I shouldn't have done m/L
    that's what I what was doing wrong.
    Thanks
     
  6. Oct 26, 2013 #5

    haruspex

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    Rats - I noticed that but dismissed it as a typo.
     
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