Lenz's Law Homework: Calculating Induced Current & Magnetic Force

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Homework Help Overview

The discussion revolves around a problem involving Lenz's Law, specifically analyzing the induced current and magnetic forces acting on a small metal ring dropped into a magnetic field. Participants are tasked with determining the direction of the induced current and the magnetic force at different positions of the ring within the field.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the direction of induced current at various positions of the ring and question the application of the right-hand rule (RHR) to determine the magnetic forces. There is a back-and-forth regarding the correctness of the answers provided, particularly concerning the forces acting on the ring.

Discussion Status

The discussion is active, with participants revisiting their initial answers and seeking clarification on the application of Lenz's Law and the RHR. Some guidance has been offered regarding the direction of forces based on the current's direction, but there remains uncertainty about the correct answers for all cases.

Contextual Notes

Participants express confusion about the RHR technique and its visualization, indicating a need for deeper understanding of the concepts involved. There is also mention of an upcoming test, which adds urgency to the discussion.

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Homework Statement



A small metel ring, as illustrated by the picture, is dropped into a region of constant magnetic field.

For regions 1, 2 and 3, determine
(a) whether the induced current is clockwise, counterclockwise, or zero
(b) whether the magnetic force on the ring upward, downward, or zero


http://i336.photobucket.com/albums/n343/physicsdude69/phys3.jpg


Homework Equations





The Attempt at a Solution


I think that

1. The induced current is counterclockwise
2. The current is zero
3. The current is clockwise

I am not sure about these answers though, and I have no idea how to solve for the direction of force. Please explain your answers if you can help me thanks
 
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anyone?
 
Let's look at position 1. The ring is entering the magnetic field so the out-of-page magnetic field increases. The current starts to run in such a way that the induced magnetic field opposes the change in the actual field. So what will be the direction of the induced field? Consequently, using the RHR, what will be the direction of the current?
 
okay so it looks like i had reversed it then

a. should be clockwise
b. zero
c. counterclockwise

to counter the into page

but still how can i figure out the forces...this whole RHR technique confuses me so much and is so frustrating to visualize
 
correct.
Now for the forces, for the first one, you know current is going clockwise and only the bottom part of the ring is in the magnetic field. So the net force on the ring will be the net force on the very bottom part of the ring (there is a force on the left and right sides that are also in the field but they get canceled out by each other). So for #1, which way will the force be?
 
hmm so will the net force act then against the object?

such that for
a. Up
b. zero
c. down
 
right
 
Hi physicsdawg,

physicsdawg said:
hmm so will the net force act then against the object?

such that for
a. Up
b. zero
c. down

I believe one of those answers is not right for the force on the ring. Try again to apply cryptoguy's advice from post #6 carefully to all three cases. Do you see which one is incorrect?
 
yeeep, thanks for the catch alphysicist, much obliged
 
  • #10
hmm still confused, would the force then be pushing down for the first part? and the last 2 right? if I'm wrong could you tell me why i have a test today and want to know these problem explanations in and out
 
  • #11
No, the first one is in fact upwards. You know that on the bottom part of the ring, current runs to the left, according to your answer in a. Apply the RHR. You'll see that the force on the bottom of the ring points upwards.

Now take a look at part C. Now, which way does the current run in the top part (the only uncanceled part of the ring affected by the magnetic field)? Apply the RHR again and you will get the answer.
 
  • #12
aah so it will also be up?
 
  • #13
correct
 

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