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Let the p.m.f. of M be defined by f(x)=x/8,x=1,3,4.

  1. Aug 28, 2009 #1
    Let the p.m.f. of M be defined by f(x)=x/8,x=1,3,4. What is the mean of M?
    Is this the same an E(M) of a binomial?
     
  2. jcsd
  3. Aug 28, 2009 #2
    Re: p.m.f.

    I guess we have P(M=1)=1/8, P(M=3)=3/8 and P(M=4) = 4/8. These add to 1.
    So the mean is ... what? Do the computation from the definition.
    Yes, this is another name for E(M), but it is not binomial.
     
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