Talk Turbines: Converting Newtons Thrust to Watts

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SUMMARY

The discussion focuses on converting thrust measured in Newtons to power output in horsepower (HP) for Wren turbines. At 375 mph, 1 lbf of thrust equals 1 HP, but this relationship varies with speed and resistance. The formula THP = (F_n * MPH) / 375, derived from a Pratt and Whitney reference, illustrates the complexity of correlating thrust and horsepower. Factors such as altitude and air resistance significantly influence this relationship, indicating that static thrust cannot be directly equated to horsepower without considering additional variables.

PREREQUISITES
  • Understanding of thrust and horsepower relationships
  • Familiarity with Wren turbines and their specifications
  • Knowledge of basic physics principles, particularly force and energy
  • Awareness of aerodynamic concepts, including air resistance
NEXT STEPS
  • Research the derivation and application of the formula THP = (F_n * MPH) / 375
  • Explore the concept of thrust curves in relation to centrifugal pumps
  • Study the effects of altitude on thrust-to-horsepower ratios
  • Investigate the performance characteristics of Wren turbines at varying speeds
USEFUL FOR

Aerospace engineers, mechanical engineers, and anyone involved in turbine design or performance analysis will benefit from this discussion.

willib
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Jet engines have a thrust horsepower calculation, but I don't think it could be held applicable in this case. The rule is at 375 mph, 1 Lbf of thrust is equal to 1 HP.
 
These Wren turbines are just under three inches in diameter..
very cool stuff..
 
Hey Fred, that works out, because if you say an aircraft is flying at 375 mph and that aircraft requires 1 lbf of thrust to keep it going at that speed, the power (force times distance per unit time) works out to 1 hp. But that's an arbitrary velocity. If the aircraft has more resistance, and can only fly at 100 mph with the same engine, then the equation results in a power output of 0.2667 hp. And if it's zipping along at 1000 mph, the power output becomes 2.667 hp.

So there doesn't seem to be a correlation between hp and thrust. But there should be since the power actually equates to energy in (ie: energy burned in the engine).

I always wondered about this one, how can you equate thrust to hp? Perhaps because it's "static thrust" one must be able to get a "thrust curve" which is analogous to a pressure curve on a centrifugal pump, along with an efficiency.

There has to be more to it than simply thrust at 375 mph equates to a given hp.
 
Q_Goest said:
Hey Fred, that works out, because if you say an aircraft is flying at 375 mph and that aircraft requires 1 lbf of thrust to keep it going at that speed, the power (force times distance per unit time) works out to 1 hp. But that's an arbitrary velocity. If the aircraft has more resistance, and can only fly at 100 mph with the same engine, then the equation results in a power output of 0.2667 hp. And if it's zipping along at 1000 mph, the power output becomes 2.667 hp.

So there doesn't seem to be a correlation between hp and thrust. But there should be since the power actually equates to energy in (ie: energy burned in the engine).

I always wondered about this one, how can you equate thrust to hp? Perhaps because it's "static thrust" one must be able to get a "thrust curve" which is analogous to a pressure curve on a centrifugal pump, along with an efficiency.

There has to be more to it than simply thrust at 375 mph equates to a given hp.

You do bring up good points. Personally I have NEVER expressed a thrust producing engine in terms of horsepower. It is always in thrust. For some (unknown to me) reason there is a small need to express HP in this fashion. The relationship THP = \frac{F_n * MPH}{375} is actually from a Pratt and Whitney reference I have. It is the only reference I have that even states it. What it's method of derivation is I really do not know.
 
Oops my mistake..
please disregard..
 
FredGarvin said:
The relationship THP = \frac{F_n * MPH}{375} is actually from a Pratt and Whitney reference I have. It is the only reference I have that even states it. What it's method of derivation is I really do not know.
As I understand it, hp:thrust ratio depends on not only speed, but also altitude. I assume that it has something to do with factoring in air resistance.
It always bugs me that a full-throttle jet bolted to a test stand produces zero horesepower.
 

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