the following?: low-spin d5 metal. Energy = -2Δ -4K (where K is exchange energy. i,e. minimization of energy due to parallel spins) low-spin d6 metal. Energy = -1.6Δ -3K Therefore: energy needed to add an electron = ΔE= 0.4Δ + K Is that correct? maybe I should be talking about Spin Pairing Energy (P) .... HEEEEEEEEEEEEEEEEEEEEEEEEEEEELP!!!!